Jude Andre Charles
Something like that:
https://www.ck12.org/c/geometry/
look up the item Reasoning and Proof
and how to find out unknown values by triangles and other figures.
These are interesting exercises .
Pi number
Jude Andre Charles the construction is proportional. You change the slope, everything changes at the same time.
Yes. But you need π as fixed value that doesn’t change. this is the key problem.
C.B. in the configuration I showed you, 3.144606 is practically everywhere... And always constant.
Jude Andre Charles in the configuration I showed you, 3.144606 is practically everywhere... And always constant.
this is not the point.
Is everywhere because you’re using certain parameters but it doesn’t mean that you proved the exact value of π .
Basically you don’t even know the exact value of the angle and so is everything a kind of approximation.
Ok, you like to approximate it to 3.1446 but thats it, a possibility not a fixed or exact value of π.
Take π as example. π is the quotient btw Perimeter and Diameter and you can change the diameter or the perimeter as often as you want but the quotient remains always π.
With the pyramid it doesn’t happen, you change the slope and everything changes.
See you tomorrow!
C.B. the key is in the construction. It is unfortunate that I cannot find the video from Samuel Laboy showing the construction, and out of it, through the calculations as shown previously, I was able to find 3.144606 almost if not every where throughout the construction where the ratio is 1:1.272019649514.
From that construction, I devised an equation which if you try it should be equal to the radius of a circle perfectly.
If, let's say the radius is 4, and half the side of a square is 3.14159265359, through the calculations, if all balances, then the result of the calculation should be the same as the radius.
Jude Andre Charles the key is in the construction.
Yes. namely, you have to have some structure or length in you diagram made out of straight lines representing the π value…like for ex. 4b=π. This you can measure and find out the numerical value pf π. Otherwise, without this link with the circle, you’re speculating or just approaching the exact value.
C.B. but the simplicity of your derivation is deceptive. That's why I want you to show me how you arrive to 3.144606 using 4b=pi. This only represents a square with a perimeter of Pi. I would like for you to explain in details your reasoning so that I may see what you see.
Jude Andre Charles but the simplicity of your derivation is deceptive.
Is not deceptive. You just have to pay attention when you read it.
Setting up 4b=π has the unique attribute that the square and the circle have areas b2 and b respectively.
Because of that we can construct a right triangle with Hypotenuse = 1 and solve over Pythagoras. thats it.
I don’t need to know if it has anything to do with Golden Ratios. I just solve it and well, there is a Golden Ratio there but I didn’t put it there. Is just a result.
C.B. if you have desmos or geogebra, can you visually show me?
C.B. I'm trying it. I don't see it
you don’t have to make any diagrams with values!
If you have b and b2 and hypotenuse 1 just use the Pythagoras theorem to solve, then you get the needed value.
b4+b2–1=0
There is no easier way.
Jude Andre Charles
You should really learn the basics of Geometry and basically how to find out hidden values in the geometric figures.
If you like that stuff you will verily enjoy it.
Maybe I'm not expressing myself correctly:
What, logically, makes it so that 3.1415 becomes 3.144606 following your equation?
I'm not new with this: you sent out 3 videos on YouTube in regards to exactly the same reasoning as that which you bring forth. From what I noticed from another who tried to ridicule your findings (Phil Webb), he failed to notice something... Something that only you can see. Open my eyes on that one. Don't send me checking basic geometry. I'm already close to 5 decades old, so basic geometry is not so far from me. I just want to understand your reasoning.
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First off, 3.14159 becomes nothing in this derivation. I don’t need it, this is a completely different approach to the π value. Just forget it.
I just did set up a circle and a square with the same perimeter π and I found out that the value of the Areas can be used to construct a right triangle and solve the value of b or π/4 over Pythagoras. That’s all what you have to understand. It is the exact value and no approximate.
Sorry about the Geometry lessons, I didn’t want to insult you.
C.B. but the reason I'm confused is that if all is of proportion, why does the lower leg of the triangle increases exponentially?
The b2 changes everything. That's why it is good once, but then breaks apart once we increase it.
C.B. or rather... Why does the square grow exponentially as opposed to the circle?
The lesser leg b2 is Ok if you leave it as it is. Why do you keep “managing” things. Take them as they are, it is enough. Just solve Pythagoras and you have what you need b=0.786. It is incontestable.
Jude Andre Charles or rather... Why does the square grow exponentially as opposed to the circle?
…..???
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